document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52412>Question 52412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3(x-0.87)-2x=4.98 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34944 by </B><A HREF=/tutors/aboutme.mpl?userid=ChillyWiz><B>ChillyWiz(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ChillyWiz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34944\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using simple algebra will solve this question\r<BR>\n" );
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document.write( "3(x-0.87)-2x = 4.98<BR>\n" );
document.write( "3x-2.41-2x = 4.98<BR>\n" );
document.write( "x-2.41 = 4.98<BR>\n" );
document.write( "x = 7.39\r<BR>\n" );
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document.write( "Step 1.  Distrubute the 3 into (x-0.87)<BR>\n" );
document.write( "Step 2.  3x minus 2x<BR>\n" );
document.write( "Step 3.  Add 2.41 to both sides </SPAN>\n" );
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