document.write( "Question 528751: the hypotenuse of a right angled triangle is 6m more than twice the shortest side. If the third side is 2m less than the hypotenuse, find the sides of the triangle. \n" ); document.write( "
Algebra.Com's Answer #349413 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! the hypotenuse of a right angled triangle is 6m more than twice the shortest side. If the third side is 2m less than the hypotenuse, find the sides of the triangle. \n" ); document.write( "Let x = shortest side \n" ); document.write( "then \n" ); document.write( "2x+6 = hypotenuse \n" ); document.write( "2x+6-2 = 2x+4 = long side \n" ); document.write( ". \n" ); document.write( "x^2 + (2x+4)^2 = (2x+6)^2 \n" ); document.write( "x^2 + (2x+4)(2x+4) = (2x+6)(2x+6) \n" ); document.write( "x^2 + 4x^2+16x+16 = 4x^2+24x+36 \n" ); document.write( "5x^2+16x+16 = 4x^2+24x+36 \n" ); document.write( "x^2+16x+16 = 24x+36 \n" ); document.write( "x^2-8x+16 = 36 \n" ); document.write( "x^2-8x-20 = 0 \n" ); document.write( "(x-10)(x+2) = 0 \n" ); document.write( "x {-2, 10} \n" ); document.write( "throw out the negative solution leaving: \n" ); document.write( "x = 10m (short side) \n" ); document.write( ". \n" ); document.write( "hypotenuse: \n" ); document.write( "2x+6 = 2(10)+6 = 20+6 = 26m \n" ); document.write( ". \n" ); document.write( "long side: \n" ); document.write( "2x+4 = 2(10)+4 = 20+4 = 24m \n" ); document.write( " |