document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=528732>Question 528732</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 20ft. less than twice the width. of the perimeter of the rectangle is 260ft. find the length and width of the rectangle<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349408 by </B><A HREF=/tutors/aboutme.mpl?userid=mathstutor494><B>mathstutor494(120)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathstutor494><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathstutor494><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let width = x\r<BR>\n" );
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document.write( "Then length = 2x-20\r<BR>\n" );
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document.write( "Perimeter of the rectangle = 2(Length+Width) <BR>\n" );
document.write( "2( 2x-20+x) = 260<BR>\n" );
document.write( "2(3x-20) = 260<BR>\n" );
document.write( "3x-20= 130<BR>\n" );
document.write( "3x = 130+20<BR>\n" );
document.write( "x = 150/3 => 50<BR>\n" );
document.write( "Therefore Length = 2x-20 => 2*50-20 => 100-20 => 80\r<BR>\n" );
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document.write( "Ans : Length 80 ft, Width 50 ft </SPAN>\n" );
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