document.write( "Question 528644: find the equation of the parabola that passes through the point (6,10) and has a vertex at (4,3) \n" ); document.write( "
Algebra.Com's Answer #349378 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Presuming a vertical axis of symmetry, if the vertex has an -coordinate of 4, then a point 2 units to the left of the vertex will have the same function value as a point 2 units to the right of the vertex. Hence has to be on the parabola. Now that we have three non-collinear points we can uniquely determine the parabola.\r
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\n" ); document.write( "\n" ); document.write( "A parabola with a vertical axis of symmetry has an equation of the form:\r
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\n" ); document.write( "\n" ); document.write( "Given the point (4,3):\r
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\n" ); document.write( "\n" ); document.write( "Given the point (6,10)\r
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\n" ); document.write( "\n" ); document.write( "Given the point (2,10)\r
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\n" ); document.write( "\n" ); document.write( "Solve the 3X3 linear system to obtain the desired coefficients.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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