document.write( "Question 52390: Could someone please explain this problem: graph the line that passes through the point (3, -2) that has a slope of 4/3. Thanks \n" ); document.write( "

Algebra.Com's Answer #34931 by THANApHD(104) $\"\"$ $\"About$

You can put this solution on YOUR website!
Think about the general form of the graph(linear).\r
\n" ); document.write( "\n" ); document.write( " $\"y=mx%2Bc\"$
\n" ); document.write( "y,x are variables; m is slope; c is Y intercept\r
\n" ); document.write( "\n" ); document.write( "So substitude the slope to create a base function with unknown c
\n" ); document.write( " y = 4/3x + c
\n" ); document.write( "
\n" ); document.write( "Now use the co-ordinates in the function
\n" ); document.write( "
\n" ); document.write( " -2 = 4/3*3 + c
\n" ); document.write( " -2 = 4 + c
\n" ); document.write( " c = -2-4
\n" ); document.write( " c = -6\r
\n" ); document.write( "\n" ); document.write( "So your new complete equation will be, \r
\n" ); document.write( "\n" ); document.write( " Y= 4/3x-6\r
\n" ); document.write( "\n" ); document.write( "Now use different of x values Eg:-1,0,1 to generate more y values and make out the points, or Ucan use the y intercept and the given point as two points to draw the line \n" ); document.write( "

\n" );