document.write( "Question 528302: Car A is traveling at 65 MPH and car B is traveling at 120 MPH. Car B passes car A. It takes car A 5 minutes and 4 seconds to catch up to car B after car B passed car A. At what speed (MPH) does car A has to go to catch up to car B. \n" ); document.write( "
Algebra.Com's Answer #349238 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Car A is traveling at 65 MPH and car B is traveling at 120 MPH. Car B passes car A. It takes car A 5 minutes and 4 seconds to catch up to car B after car B passed car A. At what speed (MPH) does car A has to go to catch up to car B. \n" ); document.write( "** \n" ); document.write( "let x=speed over 120 (MPH) car A has to go to catch up to car B. \n" ); document.write( "120+x=total speed (MPH) car A has to go to catch up to car B. \n" ); document.write( "5 minutes and 4 seconds=5*60+4=304 seconds=(304/3600) hr \n" ); document.write( "Distance car A traveled before car B catches up=(304/3600)*120≈10.13 mi \n" ); document.write( "x=distance/travel time=10.13/(304/3600)=120 mph \n" ); document.write( "ans: \n" ); document.write( "total speed (MPH) car A has to go to catch up to car B=120+x=240 mph \n" ); document.write( " |