document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52391>Question 52391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could I get some help with the following problem: Graph the line that passes through the point (3,0) that has a slope of -2/3. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34923 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use point-slope form:<BR>\n" );
document.write( "y - y1 = m(x - x1)<BR>\n" );
document.write( "y = (-2/3)(x - 3)<BR>\n" );
document.write( "y = -2x/3 + 2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C-2x%2F3%2B2%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C-2x%2F3%2B2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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