document.write( "Question 528281: how do i write an equation for a hyperbola with the give information, vertices (-4,0) (4,0) conjugate axis length of 8 \n" ); document.write( "
Algebra.Com's Answer #349203 by Edwin McCravy(20059)\"\" \"About 
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how do i write an equation for a hyperbola with the give information, vertices (-4,0) (4,0) conjugate axis length of 8
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document.write( "The transverse axis is the line segment between the vertices (-4,0) and\r\n" );
document.write( "(4,0) which is 8 units long.  Its midpoint is the origin.  The transverse \r\n" );
document.write( "axis is horizontal so the equation is of the form:\r\n" );
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document.write( "\"x%5E2%2Fa%5E2\" - \"y%5E2%2Fb%5E2\" = 1\r\n" );
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document.write( "where a = one-half the transverse axis, which is half of 8 or 4, and\r\n" );
document.write( "where b = one-half the conjugate axis, which is half of 8 or 4, so\r\n" );
document.write( "a and b are both 4, so the equation is\r\n" );
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document.write( "\"x%5E2%2F4%5E2\" - \"y%5E2%2F4%5E2\" = 1\r\n" );
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document.write( "\"x%5E2%2F16\" - \"y%5E2%2F16\" = 1\r\n" );
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document.write( "That's the standard form, or you can clear of fractions and get\r\n" );
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document.write( "x² - y² = 16\r\n" );
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document.write( "Edwin
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