document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=528213>Question 528213</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use an inverse trigonometric function to write theta as a function of x. There is a sketch of a right triangle with 10 as the opposite side, (x+1) as the adjacent, and theta as the hypotnuse/opposite angle.\r<BR>\n" );
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document.write( "Not sure how to do this at all, please solve. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349187 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349187\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use an inverse trigonometric function to write theta as a function of x. There is a sketch of a right triangle with 10 as the opposite side, (x+1) as the adjacent, and theta as the hypotnuse/opposite angle.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "By Pythagorean Theorem, hypotenuse of given right triangle =&#8730;[10^2+(x+1)^2]<BR>\n" );
document.write( "=&#8730;[100+(x^2+2x+1)]=&#8730;(x^2+2x+101)<BR>\n" );
document.write( "hypotenuse/opposite=csc theta=&#8730;(x^2+2x+101)/10<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "arccsc[&#8730;(x^2+2x+101)/10]=theta </SPAN>\n" );
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