document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=528096>Question 528096</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a normal distribution the mean is 50 and the standard deviation is 5. Find the<BR>\n" );
document.write( "proportion of values that do not lie between 48 and 52. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349145 by </B><A HREF=/tutors/aboutme.mpl?userid=reviewermath><B>reviewermath(1029)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=reviewermath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=reviewermath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(X > 52) = P[Z>(52-50)/5] = P(Z > 0.4)= 0.3446<BR>\n" );
document.write( "P(X < 48) = P[Z < (48-50)/5] = P(Z < -0.4) = 0.3446<BR>\n" );
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document.write( "We add the two probabilities to get the proportion of values that do not lie between 48 and 52, the result is 0.6892. </SPAN>\n" );
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