document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=527917>Question 527917</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x-  log3(2x-1)=2+log3(x-2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349137 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349137\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for x- log3(2x-1)=2+log3(x-2)<BR>\n" );
document.write( "**<BR>\n" );
document.write( "log3(2x-1)=2+log3(x-2)<BR>\n" );
document.write( "log3(2x-1)-log3(x-2)=2<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log3[(2x-1)/(x-2)]<BR>\n" );
document.write( "convert to exponential form: (base(3) raised to log of number(2)=number(2x-1)/(x-2)<BR>\n" );
document.write( "3^2=(2x-1)/(x-2)=9<BR>\n" );
document.write( "2x-1=9x-18<BR>\n" );
document.write( "7x=17<BR>\n" );
document.write( "x=17/7 </SPAN>\n" );
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