document.write( "Question 528003: Need help once again, can't seem to figure this out. \r
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document.write( "Let h and g be two functions defined by
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document.write( "h(x)=(5+x)(-6+x)
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document.write( "g(x)=2-x
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document.write( "for any real number x.
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document.write( "Find h/g(3) and then find all values that are NOT in the domain of h/g. If there is more than one value, separate them with commas. \n" );
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Algebra.Com's Answer #349122 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! h(x)=(5+x)(-6+x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "h(3)=(5+3)(-6+3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "h(3)=(8)(-3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "h(3) = -24\r \n" ); document.write( "\n" ); document.write( "----------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "g(x)=2-x \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "g(3)=2-3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "g(3) = -1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(h/g)(x) = (h(x))/(g(x)) \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(h/g)(3) = (h(3))/(g(3))\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(h/g)(3) = -24/(-1)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(h/g)(3) = 24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "======================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since you CANNOT divide by zero, this means that the denominator g(x) cannot be zero.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If it were, then g(x) = 0 would mean that 2-x = 0 and that x = 2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So x = 2 makes the denominator zero. So we must exclude that from the domain.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |