document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=527857>Question 527857</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the center of a circle is at the point (-2,8) and the circle goes through the origin, whats the radius </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349038 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The radius is the distance from (-2,8) to (0,0)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+sqrt%28%28-2%29%5E2+%2B+8%5E2%29 ALIGN=MIDDLE  ALT=\"r+=+sqrt%28%28-2%29%5E2+%2B+8%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+sqrt%2868%29+=+2sqrt%2817%29 ALIGN=MIDDLE  ALT=\"r+=+sqrt%2868%29+=+2sqrt%2817%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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