document.write( "Question 527795: Please help me solve this I have a test tomorrow and I'm scared!\r
\n" ); document.write( "\n" ); document.write( "Determine whether the graph of the equation is perpendicular.\r
\n" ); document.write( "\n" ); document.write( "6y-x=-12
\n" ); document.write( "1/6x +y =3
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Algebra.Com's Answer #349025 by Alan3354(69443)\"\" \"About 
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Determine whether the graph of the equation is perpendicular.\r
\n" ); document.write( "\n" ); document.write( "6y-x=-12
\n" ); document.write( "1/6x +y =3
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\n" ); document.write( "Find the slope, m, of each equation.
\n" ); document.write( "To do that, solve for y
\n" ); document.write( "6y-x=-12
\n" ); document.write( "6y = x - 12
\n" ); document.write( "y = (1/6)x - 2
\n" ); document.write( "The slope is the coefficient of x, 1/6
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\n" ); document.write( "Do the other eqn:
\n" ); document.write( "1/6x +y =3
\n" ); document.write( "y = (-1/6)x + 3
\n" ); document.write( "The slope is -1/6
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\n" ); document.write( "If they're perpendicular, the slopes are negative inverses, or their product is -1
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\n" ); document.write( "(1/6)*(-1/6) = -1/36, not -1, so they're not perpendicular.
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\n" ); document.write( "To be perpendicular, the 2nd slope would be -6, not -1/6
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