document.write( "Question 527795: Please help me solve this I have a test tomorrow and I'm scared!\r
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document.write( "Determine whether the graph of the equation is perpendicular.\r
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document.write( "6y-x=-12
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document.write( "1/6x +y =3 \n" );
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Algebra.Com's Answer #349025 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Determine whether the graph of the equation is perpendicular.\r \n" ); document.write( "\n" ); document.write( "6y-x=-12 \n" ); document.write( "1/6x +y =3 \n" ); document.write( "------------ \n" ); document.write( "Find the slope, m, of each equation. \n" ); document.write( "To do that, solve for y \n" ); document.write( "6y-x=-12 \n" ); document.write( "6y = x - 12 \n" ); document.write( "y = (1/6)x - 2 \n" ); document.write( "The slope is the coefficient of x, 1/6 \n" ); document.write( "---------- \n" ); document.write( "Do the other eqn: \n" ); document.write( "1/6x +y =3 \n" ); document.write( "y = (-1/6)x + 3 \n" ); document.write( "The slope is -1/6 \n" ); document.write( "----------- \n" ); document.write( "If they're perpendicular, the slopes are negative inverses, or their product is -1 \n" ); document.write( "-------- \n" ); document.write( "(1/6)*(-1/6) = -1/36, not -1, so they're not perpendicular. \n" ); document.write( "------------- \n" ); document.write( "To be perpendicular, the 2nd slope would be -6, not -1/6 \n" ); document.write( " \n" ); document.write( " |