document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=527727>Question 527727</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This question has to do with train speeds.\r<BR>\n" );
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document.write( "Question:  Train A leaves a station traveling at 20 mph.  Eight hours later, Train B leaves the same station traveling in the same direction at 30 mph.  How long does it take for Train B to catch up to Train A?\r<BR>\n" );
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document.write( "I have tried the Distance = Rate x Time equation, but not sure how to set up the problem to solve it.  Rate: Train A = 20 mph; Train B = 30 mph. That's as far as I get.  Please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349022 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> B catches up when it has traveled the same (equal) distance as A\r<BR>\n" );
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document.write( "(30)(t) = (20)(t + 8)\r<BR>\n" );
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document.write( "as a check ___ A travels 160 mi (8 * 20) before B leaves ___ B closes the gap at 10 mph (30 - 20) ___ how long to catch up </SPAN>\n" );
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