document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=527746>Question 527746</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hey I was having trouble with this word problem please help.( The width of a rectangle is 6 kilometers less than twice it's length. If the area is 108 square kilometers, find the dimensions of the rectangle. )How would I set this problem up? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349016 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349016\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let length = x\r<BR>\n" );
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document.write( "\"The width of a rectangle is 6 kilometers less than twice it's length\" ___ w = 2x - 6\r<BR>\n" );
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document.write( "area = length * width = x * (2x - 6) = 2x^2 - 6x\r<BR>\n" );
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document.write( "\"If the area is 108 square kilometers\" ___ 108 = 2x^2 - 6x ___ 0 = x^2 - 3x - 54\r<BR>\n" );
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document.write( "factoring ___ 0 = (x - 9)(x + 6)\r<BR>\n" );
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document.write( "so, x = 9\r<BR>\n" );
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document.write( "looks like the question switched length an width </SPAN>\n" );
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