document.write( "Question 527008: zeroes, vertical,horizontal, or oblique asymptotes of
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document.write( "(4x^2+12x+9)/(x^2-6x+5) \n" );
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Algebra.Com's Answer #348985 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! zeroes, vertical,horizontal, or oblique asymptotes of \n" ); document.write( "(4x^2+12x+9)/(x^2-6x+5) \n" ); document.write( "** \n" ); document.write( "(4x^2+12x+9)/(x^2-6x+5) \n" ); document.write( "(2x+3)^2/(x-1)(x-5) \n" ); document.write( ".. \n" ); document.write( "y-intercept \n" ); document.write( "set x=0 \n" ); document.write( "y=9/5=1.8 \n" ); document.write( ".. \n" ); document.write( "x-intercepts (zeros) \n" ); document.write( "set y=0 \n" ); document.write( "0=(2x+3)^2 \n" ); document.write( "x=-3/2 (mult. 2) \n" ); document.write( ".. \n" ); document.write( "horizontal asymptote: \n" ); document.write( "When degree of numerator and denominator are the same, divide the lead coefficients of top and bottom=4/1=4=horizontal asymptote. \n" ); document.write( ".. \n" ); document.write( "vertical asymptotes \n" ); document.write( "set denominator=0, and solve for x \n" ); document.write( "x-1=0 \n" ); document.write( "x=1 \n" ); document.write( "and \n" ); document.write( "x-5=0 \n" ); document.write( "x=5 \n" ); document.write( "Vertical asymptotes: \n" ); document.write( "x=1, and x=5 \n" ); document.write( "There are no oblique asymptotes \n" ); document.write( ".. \n" ); document.write( "number line \n" ); document.write( "<...+....-3/2....+.....1.....-.....5......+......> \n" ); document.write( " \n" ); document.write( " |