document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=527599>Question 527599</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A restauranteur is serving 300 people and believes about 15% of the patrons will order the chef's fish special. How many of the fish specials should he plan on serving in order to be pretty sure of having enough fish on hand to meet customer demand? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348971 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348971\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n=300, p=.15, q=.85,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=mu=np=300%2A.15=45 ALIGN=MIDDLE  ALT=\"mu=np=300%2A.15=45\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sigma=sqrt%28npq%29=sqrt%28300%2A.15%2A.85%29=6.185 ALIGN=MIDDLE  ALT=\"sigma=sqrt%28npq%29=sqrt%28300%2A.15%2A.85%29=6.185\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "45 + 12(about 2 standard deviations) = 57 fish specials. about a 95% chance of having enough fish on hand.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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