document.write( "Question 527520: What is the area of a rectangle that is 5 inches longer than it is wide and if you double the length and subtract 2 inches from the width the area is increased by 52 inches squared?\r
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document.write( "I tried...
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document.write( "(x-2)(2x+10)=x^2+5x+52
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document.write( "but I don't thin Im setting it up right...\r
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document.write( "Can you help me set it up? \n" );
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Algebra.Com's Answer #348930 by KMST(5328)![]() ![]() You can put this solution on YOUR website! You are properly setting it up. \n" ); document.write( "The original rectangle has a width that you called \n" ); document.write( "and we should add a requirement that it should be a real number, and that \n" ); document.write( " \n" ); document.write( "The length of the original rectangle is \n" ); document.write( "Its area is \n" ); document.write( "The new rectangle has a length of \n" ); document.write( "a width of \n" ); document.write( "(so we are also going to ask for \n" ); document.write( "The area of the new rectangle is \n" ); document.write( " \n" ); document.write( "Your equation transforms into \n" ); document.write( " \n" ); document.write( "(((x^2+x-72=0}}} \n" ); document.write( "which can be solved by factoring, or by completing the square, or by using the quadratic formula. \n" ); document.write( "One of the solutions for x is negative. The other solution is the width of the original rectangle, which you would need to use to find the area of the original rectangle. \n" ); document.write( " |