document.write( "Question 527463: could someone please show me how to find the vertex, line of symmetry, the maximum or minimum value of the quadratic function and graph the function. f(x)=5-x^2
\n" ); document.write( "Is the value, f(0)=5 a minimum or maximum? \n" ); document.write( "

Algebra.Com's Answer #348909 by swincher4391(1107) $\"\"$ $\"About$

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The vertex can be found by using the f(x) = ax^2 + bx + c where the vertex is (-b/2a, f(-b/2a) So let's find -b/2a.\r
\n" ); document.write( "\n" ); document.write( "-b/2a= -0/2(-1) = 0\r
\n" ); document.write( "\n" ); document.write( "And f(0) = 5.\r
\n" ); document.write( "\n" ); document.write( "Thus the vertex is at (0,5).\r
\n" ); document.write( "\n" ); document.write( "In a parabola, the line of symmetry is at the x-value of the vertex. So the line of symmetry is the y-axis or x=0.\r
\n" ); document.write( "\n" ); document.write( "To graph this, take the parent function y=x^2, a parabola, flip it upside down, and shift it up 5 spaces. Notice that your vertex is indeed at (0,5) at the top of the parabola. Thus f(0) = 5 is a maximum.\r
\n" ); document.write( "\n" ); document.write( "Hope this helped! \r
\n" ); document.write( "\n" ); document.write( "Please e-mail me at onlyyourmathtutor@yahoo.com if you have any other questions. \n" ); document.write( "

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