document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=527458>Question 527458</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use a right triangle where A =40 (degrees) and a = 4. solve the triangle, and round to 2 decimal places.\r<BR>\n" );
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document.write( "Thank You </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348907 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since there are 180º in a triangle, and we are given that it is a right triangle with angle 'a' being 40, that means that angle 'b' must be (90-40 = 50)º. We can then use the law of sines.\r<BR>\n" );
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document.write( "4/sin(40) = b/sin(50)\r<BR>\n" );
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document.write( "4sin(50) = bsin(40)\r<BR>\n" );
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document.write( "4sin(50)/sin(40) = b\r<BR>\n" );
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document.write( "b = 4.77\r<BR>\n" );
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document.write( "a^2 + b^2 = c^2\r<BR>\n" );
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document.write( "4^2 + (4.77)^2 = c^2\r<BR>\n" );
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document.write( "c = 6.22\r<BR>\n" );
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document.write( "Hope this helps!<BR>\n" );
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