document.write( "Question 527336: find the domain of the given function\r
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document.write( "f(y)= 1/(y+1) \n" );
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Algebra.Com's Answer #348859 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! You cannot divide by zero\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So y+1 cannot be zero\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If it were, then y + 1 = 0, which would mean that y = -1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So if y = -1, then y + 1 = 0, which would cause a division by zero error.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To avoid this, we exclude this value from the domain.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the domain is the set of all real numbers, but y cannot equal -1.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim \n" ); document.write( " |