document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=527313>Question 527313</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are (2) questions:\r<BR>\n" );
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document.write( "1. Condense the expression to the logarithm of a single quantity: 1/2 ln (2x-1) - 2 ln (x+1) \r<BR>\n" );
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document.write( "2. Solve the exponential equation algebraically: 3e^-5x = 132. \r<BR>\n" );
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document.write( "Need help answering these two questions someone please help... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348853 by </B><A HREF=/tutors/aboutme.mpl?userid=thinkinbig2><B>thinkinbig2(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thinkinbig2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1)/(2)*ln(2x-1)-2ln(x+1)\r<BR>\n" );
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document.write( "Simplify -2ln(x+1) by moving all terms inside the logarithm.  The third law of logarithms states that the logarithm of a power of x is equal to the exponent of that power times the logarithm of x (e.g. log^b(x^(n))=nlog^b(x)).<BR>\n" );
document.write( "(1)/(2)*ln(2x-1)+ln((x+1)^(-2))\r<BR>\n" );
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document.write( "Multiply (1)/(2) by ln(2x-1) to get (ln(2x-1))/(2).<BR>\n" );
document.write( "(ln(2x-1))/(2)+ln((x+1)^(-2))\r<BR>\n" );
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