document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=527241>Question 527241</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Contract the expressions. That is, use the properties of logarithms to write each expression as a single logarithm with a coefficient of 1.  \r<BR>\n" );
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document.write( "ln (3) - 2 ln (4) + ln (8)\r<BR>\n" );
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document.write( "ln (3) - 2 ln (4+8)\r<BR>\n" );
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document.write( "ln *3) - 2 (ln (4) +ln (8)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348831 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write each expression as a single logarithm with a coefficient of 1. <BR>\n" );
document.write( "ln (3) - 2 ln (4) + ln (8) = ln[3*8/4^2] = ln[24/16] = ln(3/2)<BR>\n" );
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document.write( "ln (3) - 2 ln (4+8) = ln[3/12^2] = ln[3/144]<BR>\n" );
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document.write( "ln (3) - 2 ln (4) +ln (8) = ln[3*8/4^2] = ln[24/16] =========================================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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