document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=527124>Question 527124</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hey, I've been looking all over the internet for a way to convert (y=(m)x+b) into point-slope form. I can't remember though whether this only applies to quadratic equations. If you consider this two questions, my apologies, I'm new to this.<BR>\n" );
document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348818 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Point slope form is\r<BR>\n" );
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document.write( "y - y1 = m(x - x1)\r<BR>\n" );
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document.write( "where (x1, y1) is a point that lies on the graph and m is the slope\r<BR>\n" );
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document.write( "From y = mx+b, the slope will be given. It'll be up to you find a point that lies on the graph. The easiest point is the y-intercept, which is (0, b). So x1 = 0 and y1 = b\r<BR>\n" );
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document.write( "This means that \r<BR>\n" );
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document.write( "y = mx+b \r<BR>\n" );
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document.write( "converts to\r<BR>\n" );
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document.write( "y - b = m(x - 0)\r<BR>\n" );
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document.write( "where y1 = b \r<BR>\n" );
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document.write( "Jim </SPAN>\n" );
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