document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=527131>Question 527131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using only letters from the set {A, M, T, N, Y, S}, all of the possible four-letter \"words\" are written in alphabetical oder, starting with AAAA.  What is the 2011th word in the list?  Use a systematic approach that does not involve extensive lists. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348812 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is like writing a 4-digit base6 number; where A=0, M=1, N=2, T=3, S=4, Y=5\r<BR>\n" );
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document.write( "a 4-letter word using 6 letters means 4^6 or 1296 possible words\r<BR>\n" );
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document.write( "do you start over with AAAA to get to 2011 words?\r<BR>\n" );
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document.write( "the \"second part\" of the list is 715 words (2011 - 1296)\r<BR>\n" );
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document.write( "715 in base6 is ___ 3X6^3 + 1X6^2 + 5X6^1 + 1X6^0\r<BR>\n" );
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document.write( "if you start over at 1297, the 2011th word is \"3151\" or TMYM\r<BR>\n" );
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