document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=526891>Question 526891</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find four consecutive odd integers such that 10 more than 3 times the third is 40 less than the first? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348761 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10858)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348761\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find four consecutive odd integers such that 10 more than 3 times the third is 40 less than the first?\r<BR>\n" );
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document.write( "Let the 1st integer be F\r<BR>\n" );
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document.write( "Then the others are: F + 2, F + 4, and F + 6 \r<BR>\n" );
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document.write( "We then have: 3(F + 4) + 10 = F - 40\r<BR>\n" );
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document.write( "3F + 12 + 10 = F - 40\r<BR>\n" );
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document.write( "2F + 22 = - 40\r<BR>\n" );
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document.write( "2F = - 62\r<BR>\n" );
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document.write( "F, or 1st integer = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-62%29%2F2 ALIGN=MIDDLE  ALT=\"%28-62%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or - 31\r<BR>\n" );
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document.write( "The 4 consecutive odd integers are: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28-31_-29_-27_and_-25%29 ALIGN=MIDDLE  ALT=\"highlight_green%28-31_-29_-27_and_-25%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at  MathMadEzy@aol.com </SPAN>\n" );
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