document.write( "Question 52339: when a number is decreased by 30% the result is 140, what is the number?\r
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document.write( "when 50% of a number is added to it the result if 180, what is the number?\r
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document.write( "thank you very much.. \n" );
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Algebra.Com's Answer #34867 by sumanth18(2)![]() ![]() ![]() You can put this solution on YOUR website! when a number is decreased by 30% the result is 140, what is the number? \r \n" ); document.write( "\n" ); document.write( "Lets begin by assuming the original number to be X. \n" ); document.write( "Then according to the statement : \n" ); document.write( " \n" ); document.write( " X-(30/100)*X= 140\r \n" ); document.write( "\n" ); document.write( "Multiply be denominator 100 on both sides we get, \n" ); document.write( "100X-30X= 14000 \n" ); document.write( "70X=14000 \n" ); document.write( "i.e X=14000/70=200 \n" ); document.write( "Therefore the value of X=200\r \n" ); document.write( "\n" ); document.write( "Cross Verification \n" ); document.write( "------------------ \n" ); document.write( "30% of 200 is 200*30/100=60 \n" ); document.write( "Decreasing 200 by 60 we get, 200-60 =140\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2) when 50% of a number is added to it the result if 180 \n" ); document.write( "Let original number be X. \n" ); document.write( "In this case we get, \n" ); document.write( " X+(50/100)X=180 \n" ); document.write( "Solving using above way we get X=120\r \n" ); document.write( "\n" ); document.write( "Cross Verification \n" ); document.write( "------------------ \n" ); document.write( "50% of 120 is 120*50/100=60 \n" ); document.write( "Adding 60+120=180 \n" ); document.write( " \n" ); document.write( " |