document.write( "Question 526732: $6300 is invested, part of it at 10% and part of it at 6%. For a certain year the total yield is $502.00. How much invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #348668 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Total Amount invested = $6300 \n" ); document.write( "Total Profit = $502 \n" ); document.write( "Let \n" ); document.write( "Amount invested at 10% = x \n" ); document.write( "Amount invested at 6% =6300-x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Amount invested at 10% * 10% + Amount invested at 6% * 6% = Total Profit \n" ); document.write( "x*10%+(6300-x)*6% = 502 \n" ); document.write( "x(10/100)+(6300-x)(6/100)=502 \n" ); document.write( "Multiply by 100 both sides \n" ); document.write( "10x+(6300-x)*6=502*100 \n" ); document.write( "10x+37800-6x=50200 \n" ); document.write( "10x-6x=50200-37800 \n" ); document.write( "4x=12400 \n" ); document.write( "4x/4=12400/4 \n" ); document.write( "x=3100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Amount invested at 10% = x = $3100 \n" ); document.write( "Amount invested at 6% =6300-x = 6300-3100 = $3200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "==== \n" ); document.write( "x*10%+(6300-x)*6% = 502 \n" ); document.write( "3100*(10/100)+(3200)*6/100 = 502 \n" ); document.write( "31000/100+19200/100 = 502 \n" ); document.write( "310+192=502 \n" ); document.write( "502=502 \n" ); document.write( " |