document.write( "Question 526733: A silversmith has two alloys, one containing 70% silver and the other 40% silver. How much of each should be melted and combined to obtain 400 grams of an alloy containing 61% silver?
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document.write( " ______40% alloy
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document.write( "___ g 70% alloy \n" );
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Algebra.Com's Answer #348667 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Alloy one \n" ); document.write( "========= \n" ); document.write( "Amount = x grams \n" ); document.write( "Silver = 70% = 0.7 \n" ); document.write( "Alloy two \n" ); document.write( "========= \n" ); document.write( "Amount = 400-x grams \n" ); document.write( "Silver = 40% = 0.4 \n" ); document.write( "Mixture Alloy \n" ); document.write( "============ \n" ); document.write( "Amount = 400 grams \n" ); document.write( "Silver = 61% = 0.61\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(Amount of Alloy one)*sliver + (Amount of Alloy two)*sliver = (Amount of Mixture Alloy)*sliver \r \n" ); document.write( "\n" ); document.write( "(x)(0.7)+(400-x)(0.4)=400*0.61 \n" ); document.write( "0.7x+160-0.4x=244 \n" ); document.write( "0.7x-0.4x=244-160 \n" ); document.write( "0.3x=84 \n" ); document.write( "0.3x/0.3=84/0.3 \n" ); document.write( "x=280\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Alloy one \n" ); document.write( "========= \n" ); document.write( "Amount = x = 280 grams \n" ); document.write( "Silver = 70% = 0.7 \n" ); document.write( "Alloy two \n" ); document.write( "========= \n" ); document.write( "Amount = 400-x - 400-280 = 120 grams \n" ); document.write( "Silver = 40% = 0.4 \n" ); document.write( "Mixture Alloy \n" ); document.write( "============ \n" ); document.write( "Amount = 400 grams \n" ); document.write( "Silver = 61% = 0.61\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "120grams ______40% alloy \n" ); document.write( "280grams___ g 70% alloy \n" ); document.write( " |