document.write( "Question 526733: A silversmith has two alloys, one containing 70% silver and the other 40% silver. How much of each should be melted and combined to obtain 400 grams of an alloy containing 61% silver?
\n" ); document.write( " ______40% alloy
\n" ); document.write( "___ g 70% alloy
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Algebra.Com's Answer #348667 by Maths68(1474)\"\" \"About 
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Alloy one
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\n" ); document.write( "Amount = x grams
\n" ); document.write( "Silver = 70% = 0.7
\n" ); document.write( "Alloy two
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\n" ); document.write( "Amount = 400-x grams
\n" ); document.write( "Silver = 40% = 0.4
\n" ); document.write( "Mixture Alloy
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\n" ); document.write( "Amount = 400 grams
\n" ); document.write( "Silver = 61% = 0.61\r
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\n" ); document.write( "\n" ); document.write( "(Amount of Alloy one)*sliver + (Amount of Alloy two)*sliver = (Amount of Mixture Alloy)*sliver \r
\n" ); document.write( "\n" ); document.write( "(x)(0.7)+(400-x)(0.4)=400*0.61
\n" ); document.write( "0.7x+160-0.4x=244
\n" ); document.write( "0.7x-0.4x=244-160
\n" ); document.write( "0.3x=84
\n" ); document.write( "0.3x/0.3=84/0.3
\n" ); document.write( "x=280\r
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\n" ); document.write( "\n" ); document.write( "Alloy one
\n" ); document.write( "=========
\n" ); document.write( "Amount = x = 280 grams
\n" ); document.write( "Silver = 70% = 0.7
\n" ); document.write( "Alloy two
\n" ); document.write( "=========
\n" ); document.write( "Amount = 400-x - 400-280 = 120 grams
\n" ); document.write( "Silver = 40% = 0.4
\n" ); document.write( "Mixture Alloy
\n" ); document.write( "============
\n" ); document.write( "Amount = 400 grams
\n" ); document.write( "Silver = 61% = 0.61\r
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\n" ); document.write( "\n" ); document.write( "120grams ______40% alloy
\n" ); document.write( "280grams___ g 70% alloy
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