document.write( "Question 52341This question is from textbook Beginnning Algebra
\n" ); document.write( ": I need some help with this problem.\r
\n" ); document.write( "\n" ); document.write( "Solve by completing the square.\r
\n" ); document.write( "\n" ); document.write( "2x^2+8x+3=0
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Algebra.Com's Answer #34866 by sumanth18(2)\"\" \"About 
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A typical quadratic equation is of the form :
\n" ); document.write( " \"+a%5E2%2Ax%2Bb%2Ax%2Bc+\"=0 \r
\n" ); document.write( "\n" ); document.write( "SOlve by completing squares means to rearrange the given quadratic into the neat format demonstrated above.\r
\n" ); document.write( "\n" ); document.write( "To start this we first move the loose number to the other side ,which in our case is 3.
\n" ); document.write( "Therefore we have \r
\n" ); document.write( "\n" ); document.write( " \"+2%2Ax%5E2%2B+8%2Ax+=+-3+\"
\n" ); document.write( "Next we divide through by whatever is multiplied on the squared term,which in our case will be divided by 2.
\n" ); document.write( "Therefore we have the following \"+x%5E2%2B+4%2Ax+=+-3%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "Next step, take half of the coefficient (don't forget the sign!) of the x-term, and square it. Add this square to both sides of the equation\r
\n" ); document.write( "\n" ); document.write( "Here the co-efficient of x term in our case is 4 .
\n" ); document.write( "Therefore when we take half of the co-efficient we get 2 and sign is '+'
\n" ); document.write( "SQuaring we get 4
\n" ); document.write( " adding to both sides we get,
\n" ); document.write( "\"+x%5E2%2B+4%2Ax+%2B+4++=+-3%2F2+%2B4++\"\r
\n" ); document.write( "\n" ); document.write( "Convert the left-hand side to squared form, and simplify the right-hand side
\n" ); document.write( "(Hint : This is where the sign that you kept track of earlier comes handy.)
\n" ); document.write( " \"+%28x%2B2%29%5E2++=+-3%2F2+%2B4++\"
\n" ); document.write( "Taking square root on both sides we get,
\n" ); document.write( " (x+2)= +- \"sqrt+%282.5%29\"
\n" ); document.write( "Therefore x = +- \"sqrt%282.5%29\"-2
\n" ); document.write( "Solve for x we get ,
\n" ); document.write( "x= -1.5811-2 and x= 1.5811-2
\n" ); document.write( "i.e x= -3.5811 and x=-0.4189\r
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