document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=525622>Question 525622</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please explain this to me.\r<BR>\n" );
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document.write( "I have to graph each function and state it's domain and range.<BR>\n" );
document.write( "y = sqrt(x-3) + 3\r<BR>\n" );
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document.write( "and y = sqrt(x+1)-2\r<BR>\n" );
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document.write( "Thank you for taking the time to help me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348656 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have to graph each function and state it's domain and range.<BR>\n" );
document.write( "y = sqrt(x-3) + 3 <BR>\n" );
document.write( "and y = sqrt(x+1)-2 <BR>\n" );
document.write( "**<BR>\n" );
document.write( "y=&#8730;(x-3)+3<BR>\n" );
document.write( "Domain: <BR>\n" );
document.write( "Since there are no denominators, the only restriction is in the radical.<BR>\n" );
document.write( "In all sqrts, the radican must be&#8805;0<BR>\n" );
document.write( "x-3&#8805;0<BR>\n" );
document.write( "x&#8805;3<BR>\n" );
document.write( "Domain:[3,&#8734;)<BR>\n" );
document.write( "Range:[3,&#8734;) (basic &#8730;x curve bumped up 3 units) <BR>\n" );
document.write( "..<BR>\n" );
document.write( "Graphing:<BR>\n" );
document.write( "Start with the basic &#8730;x with points at (0,0), (1,1) (9,3) and (16,4)<BR>\n" );
document.write( "Move x coordinates 3 units to the right (3,0), (4,1) (12,3) and (19,4)<BR>\n" );
document.write( "Finally, add 3 units  to the y-coordinate: (3,3), (4,4) (12,6) and (19,7)<BR>\n" );
document.write( "In effect, you are shifting the basic &#8730;x curve 3 units to the right and raising it 3 units vertically.<BR>\n" );
document.write( "see graph below as a visual check on the answers:<BR>\n" );
document.write( "..<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C%28x-3%29%5E.5%2B3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C%28x-3%29%5E.5%2B3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "..<BR>\n" );
document.write( "y=&#8730;(x+1)-2<BR>\n" );
document.write( "I will let you do this one.<BR>\n" );
document.write( "The graph below can be a visual check on your answers:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C%28x%2B1%29%5E.5-2%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C%28x%2B1%29%5E.5-2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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