document.write( "Question 525623: I would really appreciate your help.
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document.write( "I'm not sure how to go about this.\r
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document.write( "I have to graph each function and state it's domain and range.
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document.write( "y = sqrt (x+2) -2\r
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document.write( "Thanks so much. \n" );
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Algebra.Com's Answer #348653 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! I have to graph each function and state it's domain and range. \n" ); document.write( "y = sqrt (x+2) -2 \n" ); document.write( "** \n" ); document.write( "y=√(x+2)-2 \n" ); document.write( "Domain: \n" ); document.write( "Since there are no denominators, the only restriction is in the radical. \n" ); document.write( "In all sqrts, the radican must be≥0 \n" ); document.write( "x+2≥0 \n" ); document.write( "x≥-2 \n" ); document.write( "Domain:[-2,∞) \n" ); document.write( "Range:[-2,∞) (basic √x curve moved down 2 units) \n" ); document.write( ".. \n" ); document.write( "Graphing: Selecting four convenient points on the curve: \n" ); document.write( "Start with the basic √x with points at (0,0), (1,1) (9,3) and (16,4) \n" ); document.write( "Move x coordinates 2 units to the left (-2,0), (-1,1) (7,3) and (14,4) \n" ); document.write( "Finally, minus 2 units from the y-coordinate: (-2,-2), (-1,-1) (7,1) and (14,2) \n" ); document.write( "In effect, you are shifting the basic √x curve two units to the left and dropping it 2 units vertically. \n" ); document.write( "see graph below as a visual check on the answers: \n" ); document.write( ".. \n" ); document.write( " |