document.write( "Question 526691: THIS YEAR MARY'S AGE IS ONE SIXTH OF HER MOTHER. NEXT YEAR MARY'S AGE IS ONE FIFTH OF HER MOTHER. IN HOW MANY YEARS WILL MARY'S AGR BE ONE THIRD OF HER MOTHER? \n" ); document.write( "
Algebra.Com's Answer #348649 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( " \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "given: \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "---------------------- \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "Substitute (1) into (2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "and \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "------------ \n" ); document.write( "Mary is 4 now, and her Mother is 24 \n" ); document.write( "Let \n" ); document.write( "Mary's age will be 1/3 of her mother's \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "In 6 years, Mary's age will be 1/3 her Mother's \n" ); document.write( "check answer: \n" ); document.write( "In 6 years, Mary will be 10 \n" ); document.write( "In 6 years Mother will be 30 \n" ); document.write( "Mary will be 1/3 her Mother's age \n" ); document.write( " |