document.write( "Question 526678: by wieght, one fertilizer is 20% pottassium, 30% nitrogen, and 50% phosphorus. a second fertilizer has percents of 10, 30, and 60, respectively, and a third fertilizer has percents of 0, 20, 80, respectively.
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document.write( "How much of each must be mixed to get 200lb of fertilizer with percents of 12, 28.5, 59.5, respectively? \n" );
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Algebra.Com's Answer #348642 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! by weight, \n" ); document.write( "A fertilizer is 20% potassium, 30% nitrogen, and 50% phosphorus. \n" ); document.write( "B fertilizer has percents of 10, 30, and 60, \n" ); document.write( "C fertilizer has percents of 0, 20, 80, respectively. \n" ); document.write( "------ \n" ); document.write( "How much of each must be mixed to get 200lb of fertilizer with percents of 12, 28.5, 59.5, respectively? \n" ); document.write( "--- \n" ); document.write( "Equations: \n" ); document.write( "Potassium Eq: 0.20a + 0.10b + 0*c = 0.12*200 \n" ); document.write( "Nitrogen Eq:: 0.30a + 0.30b + 0.20c = 0.285*200 \n" ); document.write( "Phosphorus Eq:0.50a + 0.60b + 0.80c = 0.595*200 \n" ); document.write( "----------------------------------------------- \n" ); document.write( "I used a matrix method to get: \n" ); document.write( "A = 70 lbs. \n" ); document.write( "B = 100 lbs \n" ); document.write( "C = 30 lbs. \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |