document.write( "Question 52207This question is from textbook
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document.write( ": a quake sends out two waves at 8.9km/s and 5.1km/s. a siesmograph records the arrival of the 8.9km/s wave 73 seconds before the 5.1km/s wave. what is the distance from the siesmograph to the center of the quake? \n" );
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Algebra.Com's Answer #34864 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Use the distance formula: d = rt where: d = distance, r = rate (speed), and t = time. \n" ); document.write( "For the fast wave (8.9 km/s): \n" ); document.write( "d = (8.9 km/s)t secs. \n" ); document.write( "For the slower wave (5.1 km/s): \n" ); document.write( "d = (5.1 km/s)(t+73)secs. (It takes 73 seconds longer for this wave to reach the seismograph)\r \n" ); document.write( "\n" ); document.write( "Since the distances, d, are the same, you can write: \n" ); document.write( "(8.9 km/s)t = (5.1 km/s)(t+73)secs. Simplify and solve for t. \n" ); document.write( "8.9t = 5.1t + 372.3 Subtract 5.1t from both sides of the equation. \n" ); document.write( "3.8t = 372.3 Divide both sides by 3.8 \n" ); document.write( "t = 98 Rounded to the nearest second. (t = 97.973684...) Now substitute this value of t into either of the two initial equations and solve for d, the distance. Let's do both just to check!\r \n" ); document.write( "\n" ); document.write( "d = (8.9 km/s)(98 s) \n" ); document.write( "d = 872.2 km\r \n" ); document.write( "\n" ); document.write( "d = (5.1 km/s)(98+73) s. \n" ); document.write( "d = (5.1)(171) \n" ); document.write( "d = 872.1 km\r \n" ); document.write( "\n" ); document.write( "The epicenter of the 'quake is 872 km (rounded to the nearest km.) from the seismograph. \n" ); document.write( " |