document.write( "Question 526667: a passenger train leaves the station 3 hours after a freight train left the same station. the freight train travels 30 mph slower than the passenger train. Find the rate of each if the passenger train catches up with the freight traing in 4 hours \n" ); document.write( "

Algebra.Com's Answer #348634 by oberobic(2304) $\"\"$ $\"About$

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Freight Train.
\n" ); document.write( "d = r*t
\n" ); document.write( "t = 7 hr
\n" ); document.write( "r = x mph
\n" ); document.write( ".
\n" ); document.write( "Passenger Train.
\n" ); document.write( "d = r*t
\n" ); document.write( "t = 4 hr
\n" ); document.write( "r = x+30 mph
\n" ); document.write( ".
\n" ); document.write( "When the passenger train overtakes the freight train, they will have traveled the same distance, 'd'.
\n" ); document.write( ".
\n" ); document.write( "d = d
\n" ); document.write( "so
\n" ); document.write( "7*x = 4*(x+30)
\n" ); document.write( "7x = 4x + 120
\n" ); document.write( "3x = 120
\n" ); document.write( "x = 40 mph = speed of freight train
\n" ); document.write( ".
\n" ); document.write( "x+30 = 70 = speed of passenger train
\n" ); document.write( ".
\n" ); document.write( "Do the distance work out?
\n" ); document.write( "7 * 40 = 280 miles
\n" ); document.write( "4 * 70 = 280 miles
\n" ); document.write( "Correct.
\n" ); document.write( ".
\n" ); document.write( "Done. \n" ); document.write( "

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