document.write( "Question 526664: How much pure acid should be mixed with 2 gallons of an 80% acid solution in order to get a 90% acid solution.\r
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Algebra.Com's Answer #348612 by oberobic(2304)\"\" \"About 
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You have 2 gal. @ 80%, which is .8*2 = 1.6 gal. of pure acid.
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\n" ); document.write( "You need add 'x' gallons of 100% pure acid to make a 90% solution.
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\n" ); document.write( ".8*2 + 1*x = .9(2+x)
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\n" ); document.write( "1.6 + x = 1.8 + .9x
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\n" ); document.write( "multiply by 10 to eliminate decimals
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\n" ); document.write( "16 + 10x = 18 + 9x
\n" ); document.write( "x = 2
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\n" ); document.write( "Answer: Add 2 gallons of pure acid to 2 gallons of 80% acid to make a 90% acid solution.
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\n" ); document.write( "Check the answer:
\n" ); document.write( ".8*2 = 1.6 gal of pure acid in the original 2 gal.
\n" ); document.write( "1.6 + 2 = 3.6 gal of pure acid in the final solution.
\n" ); document.write( "3.6/4 * 100 = 90%.
\n" ); document.write( "Correct.
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\n" ); document.write( "Done.
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