document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=526562>Question 526562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jim has 11 coins in dimes and quarters.their value is 1.70 how many of each does he have and how did you fiuger this out </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348561 by </B><A HREF=/tutors/aboutme.mpl?userid=zoomkaboom4><B>zoomkaboom4(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=zoomkaboom4><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=zoomkaboom4><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Guess and Check would be the best way to solve this problem.<BR>\n" );
document.write( "Since a dime is worth 10 cents and a quarter is worth 25 cents, and there has to be 11 coins, We can just keep trying different things. \r<BR>\n" );
document.write( "\n" );
document.write( "1st attempt: 6(.25)+5(.10) =<BR>\n" );
document.write( "             1.50+.50 = $2.00 (Not the answer)\r<BR>\n" );
document.write( "\n" );
document.write( "2nd attempt: 5(.25)+6(.10) = <BR>\n" );
document.write( "             1.25+.60 = $1.85 (Not the answer)\r<BR>\n" );
document.write( "\n" );
document.write( "3rd attempt: 4(.25)+7(.10) =<BR>\n" );
document.write( "             1.00+.70 = $1.70 (The answer)\r<BR>\n" );
document.write( "\n" );
document.write( "After guessing and checking, We now know that the answer is 4 quarters and 7 dimes. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );