document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=526505>Question 526505</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: Bill is nine years older than Jack. In Six years Bill will be twice as old as Jack. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348547 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let B = Bill's present age and J = Jack's present age, then...<BR>\n" );
document.write( "1) B = J+9 \"Bill is nine years older than Jack.\"<BR>\n" );
document.write( "2) B+6 = 2(J+6) \"In six years Bill will be twice as old as Jack.\"<BR>\n" );
document.write( "Substitute B = J+9 from equation 1) for the B in equation 2) to get:<BR>\n" );
document.write( "(J+9)+6 = 2(J+6) Simplify.<BR>\n" );
document.write( "J+15 = 2J+12 Subtract J from both sides.<BR>\n" );
document.write( "15 = J+12 Subtract 12 from both sides.<BR>\n" );
document.write( "3 = J<BR>\n" );
document.write( "Jack's present age is 3 years and Bill's present age is 3+9 = 12 years. </SPAN>\n" );
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