document.write( "Question 526486: Evaluate: x^2-5x+3 for x=-5 \n" ); document.write( "
Algebra.Com's Answer #348541 by nerdybill(7384)\"\" \"About 
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Evaluate: x^2-5x+3 for x=-5
\n" ); document.write( "replace x with a -5 and solve:
\n" ); document.write( "x^2-5x+3
\n" ); document.write( "(-5)^2-5(-5)+3
\n" ); document.write( "25-5(-5)+3
\n" ); document.write( "25-(-25)+3
\n" ); document.write( "25+25+3
\n" ); document.write( "53
\n" ); document.write( "
\n" );