document.write( "Question 526467: Problem solving:
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document.write( "Riding a bike. Cesar enjoys riding his bike from Washington, DC to Bethesda, Maryland and back a total of 30 miles on the Capital Crescent path. The trip to Bethesda is uphill most of the distance. The bike's average speed going to Bethesda is 5 mph slower than the average speed returning to DC. If the round trip takes 4.5 hours, find the average speed in each direction.
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document.write( "Please explain and show me the formula you plan to use to solve the problem.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #348531 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Returning to DC speed = x mph \n" ); document.write( "Going to Bethesda x-5 mph\r \n" ); document.write( "\n" ); document.write( "Distance between them is 30 miles\r \n" ); document.write( "\n" ); document.write( "Time going to bethseda + time returning to Dc = 4.5 hours\r \n" ); document.write( "\n" ); document.write( "t=d/r\r \n" ); document.write( "\n" ); document.write( "15/x + 15/(x-5)= 4.5 hours\r \n" ); document.write( "\n" ); document.write( "LCD = x(x-5)\r \n" ); document.write( "\n" ); document.write( "Multiply by LCD \r \n" ); document.write( "\n" ); document.write( "15(x-5)+15x=4.5 * x(x-5) \n" ); document.write( "15x-75+15x=4.5x^2-22.5x\r \n" ); document.write( "\n" ); document.write( "4.5x^2-52.5x+75=0 \n" ); document.write( "multiply by 2 \n" ); document.write( "9x^2-105x+150=0 \n" ); document.write( "/3 \n" ); document.write( "3x^2-35x+50=0\r \n" ); document.write( "\n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( " \n" ); document.write( "a= 3 , b= -35 , c= 50 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 1225 + -600 \n" ); document.write( "b^2-4ac= 625 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 35 + 25 )/ 6 \n" ); document.write( "x1= 10.00 \n" ); document.write( "x2=( 35 -25 ) / 6 \n" ); document.write( "x2= 1.67 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=10 \n" ); document.write( "Speed returning = 10 mph \n" ); document.write( "Speed while going is 5 mph \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |