document.write( "Question 526349: In one car rental shop they charge $20 per day with car with an additional 14 cents per mile driven. Another car rental shop charges $22 per day with an additional 10 cents per mile driven. How many miles will the cost of both rental car fees be the same? \n" ); document.write( "
Algebra.Com's Answer #348521 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Miles = x \n" ); document.write( "Day = d\r \n" ); document.write( "\n" ); document.write( "Change dollar into cents \n" ); document.write( "$20=20*100=2000cents \n" ); document.write( "$22=22*100=2200cents\r \n" ); document.write( "\n" ); document.write( "2000*d+x*14 = 2200*d+x10 \n" ); document.write( "2000d+14x=2200d+10x \n" ); document.write( "14x-10x=2200-2000 \n" ); document.write( "4x=200 \n" ); document.write( "x=200/4 \n" ); document.write( "x=50 \n" ); document.write( "For 50 miles the cost of both rental car fees will be the same\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "======\r \n" ); document.write( "\n" ); document.write( "Miles = 50 \n" ); document.write( "Day = 1\r \n" ); document.write( "\n" ); document.write( "One Company will Charge for one day and 50 miles\r \n" ); document.write( "\n" ); document.write( "1 day charges = $20 \n" ); document.write( "50 miles charges = 14*50=700cents=$7\r \n" ); document.write( "\n" ); document.write( "Total Charges = 20+7=$27\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Other Company will Charge for one day and 50 miles\r \n" ); document.write( "\n" ); document.write( "1 day charges = $22 \n" ); document.write( "50 miles charges = 10*50=500cents=$5\r \n" ); document.write( "\n" ); document.write( "Total Charges = 22+5=$27 \n" ); document.write( " \n" ); document.write( " |