document.write( "Question 526349: In one car rental shop they charge $20 per day with car with an additional 14 cents per mile driven. Another car rental shop charges $22 per day with an additional 10 cents per mile driven. How many miles will the cost of both rental car fees be the same? \n" ); document.write( "
Algebra.Com's Answer #348521 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Miles = x
\n" ); document.write( "Day = d\r
\n" ); document.write( "\n" ); document.write( "Change dollar into cents
\n" ); document.write( "$20=20*100=2000cents
\n" ); document.write( "$22=22*100=2200cents\r
\n" ); document.write( "\n" ); document.write( "2000*d+x*14 = 2200*d+x10
\n" ); document.write( "2000d+14x=2200d+10x
\n" ); document.write( "14x-10x=2200-2000
\n" ); document.write( "4x=200
\n" ); document.write( "x=200/4
\n" ); document.write( "x=50
\n" ); document.write( "For 50 miles the cost of both rental car fees will be the same\r
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\n" ); document.write( "\n" ); document.write( "Check
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\n" ); document.write( "\n" ); document.write( "Miles = 50
\n" ); document.write( "Day = 1\r
\n" ); document.write( "\n" ); document.write( "One Company will Charge for one day and 50 miles\r
\n" ); document.write( "\n" ); document.write( "1 day charges = $20
\n" ); document.write( "50 miles charges = 14*50=700cents=$7\r
\n" ); document.write( "\n" ); document.write( "Total Charges = 20+7=$27\r
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\n" ); document.write( "\n" ); document.write( "Other Company will Charge for one day and 50 miles\r
\n" ); document.write( "\n" ); document.write( "1 day charges = $22
\n" ); document.write( "50 miles charges = 10*50=500cents=$5\r
\n" ); document.write( "\n" ); document.write( "Total Charges = 22+5=$27
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