document.write( "Question 526441: solve for x\r
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document.write( "log x +log(x-15)=2 \n" );
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Algebra.Com's Answer #348516 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! log x +log(x-15)=2 \n" ); document.write( "log x(x-15)=2 \n" ); document.write( "x(x-15)=10^2 \n" ); document.write( "x^2-15x=100 \n" ); document.write( "x^2-15x-100=0 \n" ); document.write( "(x-20)(x+5) = 0 \n" ); document.write( "x = {-5, 20} \n" ); document.write( "we can throw out the negative solution (extraneous) leaving: \n" ); document.write( "x = 20 \n" ); document.write( " |