document.write( "Question 526441: solve for x\r
\n" ); document.write( "\n" ); document.write( "log x +log(x-15)=2
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Algebra.Com's Answer #348516 by nerdybill(7384)\"\" \"About 
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log x +log(x-15)=2
\n" ); document.write( "log x(x-15)=2
\n" ); document.write( "x(x-15)=10^2
\n" ); document.write( "x^2-15x=100
\n" ); document.write( "x^2-15x-100=0
\n" ); document.write( "(x-20)(x+5) = 0
\n" ); document.write( "x = {-5, 20}
\n" ); document.write( "we can throw out the negative solution (extraneous) leaving:
\n" ); document.write( "x = 20
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