document.write( "Question 526370: The area of the rectangle is 80 square centimeters. If the perimeter is 36 centimeters, find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #348459 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! P = 2(L+W) \n" ); document.write( "P = 36 \n" ); document.write( "2L + 2W = 36 \n" ); document.write( ". \n" ); document.write( "L * W = 80 \n" ); document.write( "so \n" ); document.write( "L = 80/W \n" ); document.write( ". \n" ); document.write( "substitute \n" ); document.write( ". \n" ); document.write( "2(80/W) +2W = 36 \n" ); document.write( ". \n" ); document.write( "multiply both sides by W to eliminate the fraction \n" ); document.write( ". \n" ); document.write( "2(80) + 2W*W = 36W \n" ); document.write( ". \n" ); document.write( "divide both sides by 2 \n" ); document.write( ". \n" ); document.write( "80 + W^2 = 18W \n" ); document.write( ". \n" ); document.write( "W^2 -18W +80 = 0 \n" ); document.write( ". \n" ); document.write( "factor \n" ); document.write( ". \n" ); document.write( "(W -8)(W-10) = 0 \n" ); document.write( ". \n" ); document.write( "W = 8 or 10 \n" ); document.write( "which means \n" ); document.write( "L = 10 or 8 \n" ); document.write( "respectively \n" ); document.write( ". \n" ); document.write( "Answer: Length = 10 and Width = 8 OR Length = 8 and Width = 10. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |