document.write( "Question 526286: A freight train leaves a station at 5 A.M and travels North at 55 mph. At 6 A.M, a passanger train leaves on a parallel track and travels North at 60 mph. How long will it take the passanger train to overtake the freigh train?
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Algebra.Com's Answer #348456 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! Start with the distance equation: d=r*t \n" ); document.write( ". \n" ); document.write( "Train 1. \n" ); document.write( "d = 55t \n" ); document.write( ". \n" ); document.write( "Train 2. \n" ); document.write( "d = 60(t-1) \n" ); document.write( ". \n" ); document.write( "When Train 2 overtakes Train 1, they will have traveled the same distance. \n" ); document.write( ". \n" ); document.write( "d=d \n" ); document.write( "so \n" ); document.write( "55t = 60(t-1) \n" ); document.write( "55t = 60t -60 \n" ); document.write( "-5t = -60 \n" ); document.write( "t = 12 \n" ); document.write( ". \n" ); document.write( "Train 1 will have been traveling for 12 hr when Train 2 overtakes it. \n" ); document.write( "Train 2 will have been traveling for 11 hr when it overtakes Train 1. \n" ); document.write( ". \n" ); document.write( "Check: Will they have traveled the same distance? \n" ); document.write( "55*12 = 660 \n" ); document.write( "60*11 = 660 \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |