document.write( "Question 526253: solve each system by substitution\r
\n" ); document.write( "\n" ); document.write( "4x-4y=-16
\n" ); document.write( "y=4x+22
\n" ); document.write( "

Algebra.Com's Answer #348378 by Maths68(1474)\"\" \"About 
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4x-4y=-16........(1)
\n" ); document.write( "y=4x+22 .........(2)\r
\n" ); document.write( "\n" ); document.write( "Put the value of y from (2) to (1)
\n" ); document.write( "4x-4y=-16
\n" ); document.write( "4x-4(4x+22)=-16
\n" ); document.write( "4x-16x-88=-16
\n" ); document.write( "4x-16x-88=-16
\n" ); document.write( "-12x=88-16
\n" ); document.write( "-12x=72
\n" ); document.write( "-12x/-12=72/-12
\n" ); document.write( "x=-6\r
\n" ); document.write( "\n" ); document.write( "Put the value of x in (2)\r
\n" ); document.write( "\n" ); document.write( "y=4(-6)+22 .........(2)
\n" ); document.write( "y=-24+22
\n" ); document.write( "y=-2\r
\n" ); document.write( "\n" ); document.write( "x,y=-6,-2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "=====
\n" ); document.write( "Put the value of x and y in (1)
\n" ); document.write( "4x-4y=-16
\n" ); document.write( "4(-6)-4(-2)=-16
\n" ); document.write( "-24+8=-16
\n" ); document.write( "-16=-16
\n" ); document.write( "
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