document.write( "Question 526214: A rectangle has a length that is 2ft. longer than its width. if the area is 48ft^2, find its length and width. \n" ); document.write( "

Algebra.Com's Answer #348376 by Maths68(1474) $\"\"$ $\"About$

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Area = A = 48 ft^2
\n" ); document.write( "Length = l = w+2 ft
\n" ); document.write( "Length = ?
\n" ); document.write( "Width = ?
\n" ); document.write( "Length * Width = Area of Rectangle
\n" ); document.write( "l*w=A
\n" ); document.write( "(w+2)*(w) = 48
\n" ); document.write( "w^2+2w = 48
\n" ); document.write( "w^2+2w-48=0
\n" ); document.write( "w^2-6w+8w-48=0
\n" ); document.write( "w(w-6)+8(w-6)=0
\n" ); document.write( "(w-6)(w+8)=0
\n" ); document.write( "w-6=0 or w+8=0
\n" ); document.write( "w=6 or w=-8 (inadmissble)
\n" ); document.write( "so
\n" ); document.write( "w=6
\n" ); document.write( "Width = 6 ft
\n" ); document.write( "Length = l = w+2 = 6+2 = 8 ft\r
\n" ); document.write( "\n" ); document.write( "Length is 8 ft \n" ); document.write( "

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