document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=526225>Question 526225</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of triangle 180cm. the lenght of the first side is twice lenght of second side the lenght of the third side is three times the lenght of second side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348372 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let<BR>\n" );
document.write( "Length of second side = a = x<BR>\n" );
document.write( "Length of first side = b = 2x<BR>\n" );
document.write( "Length of third side = c = 3x <BR>\n" );
document.write( "Given<BR>\n" );
document.write( "Perimeter of Triangle = P = 180cm\r<BR>\n" );
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document.write( "a+b+c=P<BR>\n" );
document.write( "x+2x+3x=180<BR>\n" );
document.write( "6x=180<BR>\n" );
document.write( "x=180/6<BR>\n" );
document.write( "x=30\r<BR>\n" );
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document.write( "Length of second side = a = x = 30 <BR>\n" );
document.write( "Length of first side = b = 2x = 2(30) = 60<BR>\n" );
document.write( "Length of third side = c = 3x = 3(30) = 90\r<BR>\n" );
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document.write( " </SPAN>\n" );
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