document.write( "Question 526139: Could someone please explain to me step by step how to complete this problem? I am able to get to the part where you simplify but am not able to get no farther.
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document.write( "During the first part of a trip, a canoeist travels 91 miles at a certain speed. The canoeist travels 2 miles on the second part of the trip at a speed 5 mph slower. The total time for the trip is 3 hrs. What was the speed on each part of the trip?
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Algebra.Com's Answer #348350 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! During the first part of a trip, a canoeist travels 61 miles at a certain speed. \n" ); document.write( " The canoeist travels 2 miles on the second part of the trip at a speed 5 mph slower. \n" ); document.write( " The total time for the trip is 3 hours. What was the speed on each part of the trip? \n" ); document.write( ": \n" ); document.write( "Let s = the speed for the 1st 61 mi \n" ); document.write( "then \n" ); document.write( "(s-5) = the speed for the last 2 mi \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( ": \n" ); document.write( "faster time + slower time = 3 hrs \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "multiply by s(s-5), results: \n" ); document.write( "61(s-5) + 2s = 3s(s-5) \n" ); document.write( ": \n" ); document.write( "61s - 305 + 2s = 3s^2 - 15s \n" ); document.write( "63s - 305 = 3s^2 - 15s \n" ); document.write( "Arrange as a quadratic equation on the right \n" ); document.write( "0 = 3s^2 - 15s - 63s + 305 \n" ); document.write( "3s^2 - 78s + 305 = 0 \n" ); document.write( "Use the quadratic formula to find s: \n" ); document.write( " \n" ); document.write( "In this problem, a=3, b=-78, c=305, x=s \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Two solutions \n" ); document.write( " \n" ); document.write( "s = \n" ); document.write( "s = 21.206 \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "s = \n" ); document.write( "s = 4.794 \n" ); document.write( ": \n" ); document.write( "Obviously the only reasonable solution: \n" ); document.write( "s = 21.206 mph on the first 61 mi \n" ); document.write( "and \n" ); document.write( " 16.206 mph on the last two miles \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that check out, find the actual time of each \n" ); document.write( "61/21.206 = 2.876 hrs \n" ); document.write( "2/16.206 = .123 hrs \n" ); document.write( "---------------------- \n" ); document.write( "total time: 3.0 hrs \n" ); document.write( " |